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Ray Stainer
10-13-2001, 05:03 PM
Gentlemen.
This is something you will all know I think. I'm not young, and some new
principles become more difficult to grasp as I get older.
I am led to believe that the actual speed of rotation of a CD (either Data or Audio) is determined by the CD Driver. Why, therefore does the pitch of the audio NOT change when running a CD on a machine whose driver causes one speed of rotation and running the same CD on a machine whose driver causes a different of rotation.
If someone can kindly explain to me where my thinking is going wrong. If so I may be able to figure out all the other relationships associated with CD speeds eg. What speed driver I need to read CDs that I burn on one computer and want to read them on others etc..

Many thanks in advance

Ray Stainer
bassman
10-13-2001, 05:21 PM
Hello Ray,
The speed of different CD ROM drives is not idicative of the playing of the information stored on it. The speed at which it reads is how fast it can put that info to the RAM and processor.
This is why you can record and play a music CD at the same time, or install a program on multipul machines over a network at the same time while starting them at different times.

Does that help? http://www.PCGuide.com/ubb/wink.gif

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Ray Stainer
10-13-2001, 05:39 PM
Gentlemen,
Thank you for your help. THAT was ten lessons in ONE.

Ray Stainer
geebee76
10-13-2001, 07:13 PM
Hi Ray, In addition,

As far as I'm aware all audio CD's transfer data at the same rate, 150kb/sec, regardless of the speed of the drive.

This is the original 1xCD-ROM speed.

When you see a 40xCD-ROM, this is a multiple of the original 150kb/sec, which equals 6600 kb/sec (although this is only the theoretical maximum and only achieved while reading the outside of the disk). This only relates to the transfer of computer data, which we want to be transferred as quickly as possible unlike audio data.

As far as burning audio onto CD's, it doesn't matter what speed you burn at. This speed does not have to match the x speed of the drive you intend to play the disk on.

If I have this wrong someone will correct it.

Hope this helps http://www.PCGuide.com/ubb/smile.gif

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